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IIT JEE

Practice

Calculus

Limits

Quick practice

Question 1 of 5

Let f:\left[0, \frac{\pi}{2}\right] \longrightarrow R  be continuous and satisfy f'\mathrm{(x})=\frac{1}{1+\cos \mathrm{x}}   for all \mathrm{x} \in\left(0, \frac{\pi}{2}\right) . If f\mathrm(0)=3 , then f\left(\frac{\pi}{2}\right)  has the value equal to _____.

A

2

B

\frac{13}{4}

C

None

D

4

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